Optimal. Leaf size=65 \[ -\frac{i d \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^2}+\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i (c+d x)^2}{2 d} \]
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Rubi [A] time = 0.0963027, antiderivative size = 65, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {3717, 2190, 2279, 2391} \[ -\frac{i d \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^2}+\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i (c+d x)^2}{2 d} \]
Antiderivative was successfully verified.
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Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int (c+d x) \cot (a+b x) \, dx &=-\frac{i (c+d x)^2}{2 d}-2 i \int \frac{e^{2 i (a+b x)} (c+d x)}{1-e^{2 i (a+b x)}} \, dx\\ &=-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{d \int \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}+\frac{(i d) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^2}\\ &=-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i d \text{Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}\\ \end{align*}
Mathematica [B] time = 5.18029, size = 188, normalized size = 2.89 \[ -\frac{d \csc (a) \sec (a) \left (\frac{\tan (a) \left (i \text{PolyLog}\left (2,e^{2 i \left (\tan ^{-1}(\tan (a))+b x\right )}\right )+i b x \left (2 \tan ^{-1}(\tan (a))-\pi \right )-2 \left (\tan ^{-1}(\tan (a))+b x\right ) \log \left (1-e^{2 i \left (\tan ^{-1}(\tan (a))+b x\right )}\right )+2 \tan ^{-1}(\tan (a)) \log \left (\sin \left (\tan ^{-1}(\tan (a))+b x\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt{\tan ^2(a)+1}}+b^2 x^2 e^{i \tan ^{-1}(\tan (a))}\right )}{2 b^2 \sqrt{\sec ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}+\frac{c (\log (\tan (a+b x))+\log (\cos (a+b x)))}{b}+\frac{1}{2} d x^2 \cot (a) \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.248, size = 215, normalized size = 3.3 \begin{align*} -{\frac{i}{2}}d{x}^{2}+icx+{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{b}}-2\,{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{b}}+{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ) }{b}}-{\frac{2\,idax}{b}}-{\frac{id{a}^{2}}{{b}^{2}}}+{\frac{d\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{b}}+{\frac{d\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ) a}{{b}^{2}}}-{\frac{id{\it polylog} \left ( 2,{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}}+{\frac{d\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ) x}{b}}-{\frac{id{\it polylog} \left ( 2,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}}-{\frac{ad\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{{b}^{2}}}+2\,{\frac{ad\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.53232, size = 255, normalized size = 3.92 \begin{align*} \frac{-i \, b^{2} d x^{2} - 2 i \, b^{2} c x - 2 i \, b d x \arctan \left (\sin \left (b x + a\right ), -\cos \left (b x + a\right ) + 1\right ) + 2 i \, b c \arctan \left (\sin \left (b x + a\right ), \cos \left (b x + a\right ) - 1\right ) +{\left (2 i \, b d x + 2 i \, b c\right )} \arctan \left (\sin \left (b x + a\right ), \cos \left (b x + a\right ) + 1\right ) - 2 i \, d{\rm Li}_2\left (-e^{\left (i \, b x + i \, a\right )}\right ) - 2 i \, d{\rm Li}_2\left (e^{\left (i \, b x + i \, a\right )}\right ) +{\left (b d x + b c\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) + 1\right ) +{\left (b d x + b c\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} - 2 \, \cos \left (b x + a\right ) + 1\right )}{2 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 0.546684, size = 721, normalized size = 11.09 \begin{align*} \frac{-i \, d{\rm Li}_2\left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) + i \, d{\rm Li}_2\left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) + i \, d{\rm Li}_2\left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - i \, d{\rm Li}_2\left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) +{\left (b d x + b c\right )} \log \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) +{\left (b d x + b c\right )} \log \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right ) +{\left (b c - a d\right )} \log \left (-\frac{1}{2} \, \cos \left (b x + a\right ) + \frac{1}{2} i \, \sin \left (b x + a\right ) + \frac{1}{2}\right ) +{\left (b c - a d\right )} \log \left (-\frac{1}{2} \, \cos \left (b x + a\right ) - \frac{1}{2} i \, \sin \left (b x + a\right ) + \frac{1}{2}\right ) +{\left (b d x + a d\right )} \log \left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) +{\left (b d x + a d\right )} \log \left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right )}{2 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right ) \cos{\left (a + b x \right )} \csc{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )} \cos \left (b x + a\right ) \csc \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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